Login     Register

        Contact Us     Search

XLeratorDB/statistics Documentation

SQL Server BETA.DIST.RANGE function


BINOM_DIST_RANGE

Updated: 31 July 2015

Use BINOM_DIST_RANGE to calculate the probability of a trial result using a binomial distribution.
Syntax
SELECT [wct].[BINOM_DIST_RANGE](
  <@Trials, int,>
 ,<@Probability_s, float,>
 ,<@Number_s, int,>
 ,<@Number_s2, int,>)
Arguments
@Trials
The number of independent trials. @Trials must be of a type int or of type that intrinsically converts to int
@Probability_s
The probability of success in each trial. @Probability_s must be of a type float or of a type that intrinsically converts to float.
@Number_s
The number of successes in @Trials. @Number_s must be of a type int or of a type that intrinsically converts to int.
@Number_s2
The upper bound of the number of successes in @Trials. @Number_s2 must be of a type int or of a type that intrinsically converts to int.
Return Type
float
Remarks
·         @Trials > 0
·         0 = @Probability_s = 1
·         0 = @Number_s = @Trials
·         If NOT NULL then 0 = @Number_s2 = @Trials
Examples
Calculate the probability of having exactly 48 successes in 60 trails when the probability of success is 75%.
SELECT
       wct.BINOM_DIST_RANGE(
               60           --@Trials
              ,0.75         --@Probability_s
              ,48           --@Number_s
              ,NULL         --@Number_s2
              ) as BINOM_DIST_RANGE

This produces the following result.


This is actually no different than calculating the probability mass function of the binomial distribution.
SELECT wct.BINOMDIST(48,60,0.75,'False') as PMF

This produces the following result.


Let's look at another example where we calculate the probability of having exactly 500 successes in 1,000 trial where the probability of success is 50%.
SELECT
       wct.BINOM_DIST_RANGE(
               1000         --@Trials
              ,0.50         --@Probability_s
              ,500          --@Number_s
              ,NULL        --@Number_s2
              ) as BINOM_DIST_RANGE

This produces the following result.


It might be far more useful, however, to calculate the probability of having between 450 and 550 successes.
SELECT
       wct.BINOM_DIST_RANGE(
               1000         --@Trials
              ,0.50         --@Probability_s
              ,450          --@Number_s
              ,550          --@Number_s2
              ) as BINOM_DIST_RANGE

This produces the following result.
 


In this example we bucket the results into 20 equal groups using the XLeratorDB SeriesInt function.
SELECT
        seriesvalue-49 as lb
       ,seriesvalue as ub
       ,wct.BINOM_DIST_RANGE(1000,0.50,seriesvalue-49,seriesvalue) as p
FROM
       wct.SeriesInt(50,1000,50,NULL,NULL)

This produces the following result.

 

See Also

 



Copyright 2008-2013 WestClinTech LLC         Privacy Policy        Terms of Service